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fix: 修复缓存失效时,可能会重复获取accessToken的问题 (#762)
* fix: 修复缓存失效时,可能会重复获取accessToken的问题 * feat: 添加获取AK失败时的错误信息返回 --------- Co-authored-by: wujiaxi <wujiaxi@expandera.cn>
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@@ -90,9 +90,9 @@ func (ak *DefaultAccessToken) GetAccessTokenContext(ctx context.Context) (access
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return
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}
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if err = ak.cache.Set(accessTokenCacheKey, resAccessToken.AccessToken, time.Duration(resAccessToken.ExpiresIn-1500)*time.Second); err != nil {
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return
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}
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expires := resAccessToken.ExpiresIn - 1500
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err = ak.cache.Set(accessTokenCacheKey, resAccessToken.AccessToken, time.Duration(expires)*time.Second)
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accessToken = resAccessToken.AccessToken
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return
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}
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@@ -141,7 +141,7 @@ func (ak *StableAccessToken) GetAccessTokenContext(ctx context.Context) (accessT
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}
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expires := resAccessToken.ExpiresIn - 300
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_ = ak.cache.Set(accessTokenCacheKey, resAccessToken.AccessToken, time.Duration(expires)*time.Second)
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err = ak.cache.Set(accessTokenCacheKey, resAccessToken.AccessToken, time.Duration(expires)*time.Second)
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accessToken = resAccessToken.AccessToken
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return
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@@ -219,9 +219,7 @@ func (ak *WorkAccessToken) GetAccessTokenContext(ctx context.Context) (accessTok
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expires := resAccessToken.ExpiresIn - 1500
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err = ak.cache.Set(accessTokenCacheKey, resAccessToken.AccessToken, time.Duration(expires)*time.Second)
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if err != nil {
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return
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}
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accessToken = resAccessToken.AccessToken
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return
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}
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